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screams "delete". -Neither of the sources, all two of them, call this "the XY problem". One is said to have "implicitly coined" the term (classic SYNTH). If...

(UTC) List of Pokémon: XY episodes → List of Pokémon the Series: XY episodes – (and along with Pokémon: XY → Pokémon the Series: XY) Ok, I am totally puzzled...

cryptology, the DH problem refers to the actual problem of computing g^xy from g^x and g^y not to the "problem" of proving that this problem is hard, as done...

island, about adults and has flashbacks( kyle xy does have a form of flashbacks), everything unlike Kyle XY. The only thing I see is the whole mystery side...

October 2015 (UTC) (non-admin closure) List of Pokémon: XY episodes (part 2) → List of Pokémon: XY: Kalos Quest episodes – So this has been quite a controversial...

least one of those papers is titled 'Ovarian development in 46,XY gonadal dysgenesis'. 46,XY gonadal dysgensis is, by definition, the same thing as Swyer...

problems. Wengier Wu’s vDosPlus is an x86 PC and DOS emulator for Windows based on Jos Schaars’s vDos. Formerly known as vDos-lfn, vDosPlus allows XyWrite...

of X determines sex). However, Drosophila is an XY system -- normal females are XX; normal males are XY. While phenotypically classified as males, X0 flies...

either XY>0 or XY<0. If XY<0, one value is above the median and the other is below the median and in this case P(Y>X) = P(Y<X) = 1/2. However, if XY>0, both...

precision the original values were given (20% of xy,0 .. xy,9 - 4% of xy,00 .. xy,99 - 0,8% of xy,000 .. xy,999 and so on), thus the sterbenz lemma is a nice...

side of the equation. I have a problem with this edit. Suppose the equation is x y ′ + ( y ″ ) 2 = x 3 . {\displaystyle xy'+(y'')^{2}=x^{3}.\,} This trivially...

(UTC) The binomial term is the problem. Sigma^2 (talk) 11:23, 7 May 2021 (UTC) The variance of X Y {\displaystyle XY} is Var ⁡ ( X Y ) = E ⁡ [ ( X Y...

as Caucasian Albania came into existence is xy century and that xy ruler living in the xy territory did xy", except there is absolutely nothing of this...

XY2X + 1 = X(Y2 −1)X + (X2 + 1) ∈ A. Therefore XY(XY − YX) + XY2X + 1 ∈ A. But this final element is (XY) 2 + 1, so that A contains the quadratic polynomial...

The interpretation of the configuration xqy is that M is in state q with xy on its tape, with its head scanning the left-most symbol of y.If C and C are...

{x+y}{n}}+{\frac {xy}{n^{2}}}\right)^{n}\\&=\lim _{n\to \infty }\sum _{k=0}^{n}{\binom {n}{k}}\left(1+{\frac {x+y}{n}}\right)^{n-k}\left({\frac {xy...

|xy|=p and |z|=p, then xy is the first half of w, or all p of the as". I don't think we can do this - don't we have to consider any case where |xy| ≤...

is not potent an androgen enough to fully masculinize the genitalia of an XY individual in utero, resulting in erroneous sexing at birth. At puberty, however...

centered at ‖ X y ‖ {\displaystyle \|Xy\|} . By choosing h = y, ε = d and repeating the above, we find T in M such that ||Xy - Ty|| < d. Thus | ‖ X y ‖ − |...

P(\sum (xy_{i})>t||y||_{2})\leq e^{\frac {t^{2}}{2}}} where || ||2 is the quadratic norm and P(a) is the probability of event a. I have various problems with...