Here's some star figures (compounds) too, n{p/q} with p=2..16, q=1..p/2, and n*p<32. I colored the edges, but looks like yellow was a poor color choice. Tom Ruen (talk) 10:52, 22 January 2015 (UTC) Digon compounds added in first row. Tom Ruen (talk) 18:56, 31 January 2015 (UTC)[reply]
2{2}
3{2}
4{2}
5{2}
6{2}
7{2}
8{2}
9{2}
10{2}
2{3}
3{3}
4{3}
5{3}
6{3}
7{3}
8{3}
9{3}
10{3}
2{4}
3{4}
4{4}
5{4}
6{4}
7{4}
2{5}
3{5}
4{5}
5{5}
6{5}
2{5/2}
3{5/2}
4{5/2}
5{5/2}
6{5/2}
2{6}
3{6}
4{6}
5{6}
2{7}
3{7}
4{7}
2{7/2}
3{7/2}
4{7/2}
2{7/3}
3{7/3}
4{7/3}
2{8}
3{8}
2{8/3}
3{8/3}
2{9}
3{9}
2{9/2}
3{9/2}
2{9/4}
3{9/4}
2{10}
3{10}
2{10/3}
3{10/3}
2{11}
2{11/2}
2{11/3}
2{11/4}
2{11/5}
2{12}
2{12/5}
2{13}
2{13/2}
2{13/3}
2{13/4}
2{13/5}
2{13/6}
2{14}
2{14/3}
2{14/5}
2{15}
2{15/2}
2{15/4}
2{15/7}
6{7/2}
20{5/2}
Isogonal stars
These star polygons are isogonal (vertex-transitive), all solutions for equal-spaced vertices, p=3..16. They have two edge lengths in general, while some have equal edge lengths and are also regular: t{p/q}={2p/q} for odd(q), and t{p/(2p-q)}={2p/(2p-q)} for odd(2p-q). Tom Ruen (talk) 04:01, 29 January 2015 (UTC)[reply]
Isogonal star polygons as truncations of regular convex polygons
{3}:t2
{4}:t2
{4}:t3 t{4/3}={8/3}
{5}:t2
{5}:t3
{6}:t2
{6}:t3
{6}:t4 t{6/5}={12/5}
{7}:t2
{7}:t3
{7}:t4
{8}:t2
{8}:t3
{8}:t4
{8}:t5 t{8/7}={16/7}
{9}:t2
{9}:t3
{9}:t4
{9}:t5
{10}:t2
{10}:t3
{10}:t4
{10}:t5
{10}:t6 t{10/9}={20/9}
{11}:t2
{11}:t3
{11}:t4
{11}:t5
{11}:t6
{12}:t2
{12}:t3
{12}:t4
{12}:t5
{12}:t6
{12}:t7 t{12/11}={24/11}
{13}:t2
{13}:t3
{13}:t4
{13}:t5
{13}:t6
{13}:t7
{14}:t2
{14}:t3
{14}:t4
{14}:t5
{14}:t6
{14}:t7
{14}:t8 t{14/13}={28/13}
{15}:t2
{15}:t3
{15}:t4
{15}:t5
{15}:t6
{15}:t7
{15}:t8
{16}:t2
{16}:t3
{16}:t4
{16}:t5
{16}:t6
{16}:t7
{16}:t8
{16}:t9 t{16/15}={32/15}
Isogonal star polygons as truncations of star polygons