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C_0 semigroup: If the linear operator A is not bounded, we can not own the semigroup of linear operators Γ ( t ) = e t A {\displaystyle \Gamma (t)=e^{tA}}...

semilattice E(S) is complete (every non-empty subset A of E(S) has an infimum ⋀ e ∈ A e {\displaystyle \bigwedge _{e\in A}{e}} ). Semigroups with property...

Lipscomb's book of that's not in the more general books about inverse semigroups, e.g. in Lawson's. JMP EAX (talk) 02:55, 27 August 2014 (UTC) I just changed...

Question: How many semigroups are there of a given finite order? Is there a formula? — Preceding unsigned comment added by 203.109.250.xxx (talk) 03:04...

By way of adding clarity - the positive integers without zero are a semigroup, being a monoid with the identity deleted. However the nonzero integers...

semiautomaton. At this time, WP has five distinct articles (e.g. transformation semigroup, transition monoid, state transition system, etc.) all talking...

extremely tedious section Semigroup_with_involution#Free_semigroup_with_involution is trying to say that the only free semigroup with involution is basically...

survey of the literature suggests that ″E-inversive″ is the more common term for what this page describes than ″E-dense″. So should the article's default...

"Every E-inversive semigroup is regular, but not vice versa"; isn't this the wrong way around? eg let S={z, x} where all products equal z. This is E-inversive...

Inverse semigroups require each element to have a unique inverse, but all elements of left/right zero semigroups are inverses of each other (i.e. aba =...

Decidable for Finite Automata and Semigroups" given in Hungary should suffice as evidence: http://atlas-conferences.com/c/a/e/c/44.htm I took a course from...

spaces can be infinite, certainly the same can be true for automata, semigroups and acts, and the like, as long as the word "finite" is not invoked. Incidentally...

which I had missed. A semigroup of isometries on a metric space is automatically distal. The assumption requiring the normed space E to be Banach is not...

problems with interpreting these two statements in the Wikipedia article: A semigroup of linear operators can be strongly measurable yet not strongly continuous...

fourth example stated: Any semigroup S may be turned into a monoid simply by adjoining an element e not in S and defining ee = e and es = s = se for all...

discuss or mention these concepts? This is echoed in semigroups, to wit the empty semigroup and the semigroup with one element. — Quondum 05:07, 14 October 2013...

far, Pascal. Where do normal bands, i.e., those satisfying xyzx = xzyx, fit into the lattice? (I am not a semigroup theorist, and apologize if this is basic...

this article. Gwideman (talk) 20:18, 10 December 2009 (UTC) The term semigroup isn't defined but it is used in the article. What is the point of an article...

Laplace transform of the semigroup L T t ϕ = ∫ 0 ∞ e − λ t T t ϕ d t {\displaystyle {\mathcal {L}}T_{t}\phi =\int _{0}^{\infty }e^{-\lambda t}T_{t}\phi dt}...