1868 United States presidential election in Massachusetts

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1868 United States presidential election in Massachusetts

← 1864 November 3, 1868 1872 →
Turnout66.9[1] Increase 3.1 pp
 
Nominee Ulysses S. Grant Horatio Seymour
Party Republican Democratic
Home state Illinois New York
Running mate Schuyler Colfax Francis Preston Blair, Jr.
Electoral vote 12 0
Popular vote 136,379 59,103
Percentage 69.76% 30.23%

County Results
Grant
  50–60%
  60-70%
  70-80%
  80-90%


President before election

Andrew Johnson
Democratic

Elected President

Ulysses S. Grant
Republican

The 1868 United States presidential election in Massachusetts took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for president and vice president.

Massachusetts voted for the Republican nominee, Ulysses S. Grant, over the Democratic nominee, Horatio Seymour. Grant won the state by a margin of 39.53%.

With 69.76% of the popular vote, Massachusetts would be Grant's second strongest victory in terms of popular vote percentage after neighboring Vermont.[2]

Results

1868 United States presidential election in Massachusetts[3]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Ulysses S. Grant of Illinois Schuyler Colfax of Indiana 136,379 69.76% 12 100.00%
Democratic Horatio Seymour of New York Francis Preston Blair, Jr. of Missouri 59,103 30.23% 0 0.00%
N/A Others Others 26 0.01% 0 0.00%
Total 195,508 100.00% 12 100.00%

See also

References

  1. ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
  2. ^ "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  3. ^ "1868 Presidential General Election Results - Massachusetts".